| Title: | CALCULATIONS OF NUCLEAR REACTION PROBABILITIES IN A CRYSTAL LATTICE OF TITANIUM DEUTERIDE |
| DOI No: | 10.1142/9789812701510_0060 |
| Source: | CONDENSED MATTER NUCLEAR SCIENCE (pp 681-685)
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| Author(s): | V. A. KIRKINSKII
Institute of Mineralogy and Petrography, Siberian Branch of the Russian Academy of Sciences, Prospect Acad. Koptyuga, 3, Novosibirsk, 630090, Russia
YU. A. NOVIKOV
Institute of Mineralogy and Petrography, Siberian Branch of the Russian Academy of Sciences, Prospect Acad. Koptyuga, 3, Novosibirsk, 630090, Russia
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| Abstract: | For calculations of probability of nuclear reactions of hydrogen isotopes in the crystal lattice of titanium deuteride the model offered earlier for palladium deuteride was used. In a series of experiments the probability of D–D approach for random initial conditions was calculated, when initial energies of approaching deuterons were set in the range of energies 0.01–0.51 eV. For each experimental value of D–D approach the reaction rate was calculated on the shifted Coulomb potential with the shift energy, which equals to the energy of screening. The mean distance of D–D approach on all series equals 0.97 Å, that exceeds the mean distance in a molecule D–D. However, more than 14% of all experimental values show an approach of deuterons for a distance less than 0.1 Å. The general reaction rate for the given set of the initial conditions will make 101.91 DD−1 s−1. It is four orders of magnitude less than the analogous rate calculated earlier for palladium deuteride. For optimization of calculations the most favorable initial conditions were selected. As a result the rate of the reaction calculated according to the above model should be additionally multiplied by a correction factor, which allows for the probability of the occurrence of these favorable conditions. In our case it equals 10−16 to 10−18; the rate of the nuclear fusion reaction of deuterons in titanium deuteride should be three to four orders lower, than the earlier calculated rate for palladium deuteride and equals 10−14 to 10−16 DD−1 s−1. |
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